cot A = 1/tan A = 1/(1/√3) = √3 — (1) Using Trigonometric Identity: 1 + tan²A = sec²A 1 + (1/√3)² = sec²A sec²A = 1 + 1/3 = 4/3 sec A = +√(4/3) = +2/√3 or sec A = -2/√3 (neglecting this value as A is acute angle) Therefore, sec A = 2/√3 Using Trigonometric Identity: 1 +…
Tag: CBSE Maths
Example 2: If ∠B and ∠Q are acute angles such that sin B = sin Q, then prove that ∠B = ∠Q
To Prove: ∠B=∠Q\angle B = \angle Q Given: ∠B and ∠Q are acute angles sin B = sin Q Proof: Let us consider two right triangles: ΔABC, right-angled at C ΔPQR, right-angled at R Step 1: Write sine values in each triangle In ΔABC: sinB=ACAB⋯(1)\sin B = \frac{AC}{AB} \quad \cdots (1) In ΔPQR: sinQ=PRPQ⋯(2)\sin Q = \frac{PR}{PQ} \quad \cdots…
Why Sin A and Cos A are always less than 1 in Right Triangles – Class 10
Let’s break this down step by step so you fully understand why this is always true. 📌 What Is a Right Triangle? A right triangle is a triangle with one 90-degree angle. The side opposite this right angle is called the hypotenuse. The other two sides are called the perpendicular and the base — they are always shorter than the…