To Prove: ∠B=∠Q\angle B = \angle Q Given: ∠B and ∠Q are acute angles sin B = sin Q Proof: Let us consider two right triangles: ΔABC, right-angled at C ΔPQR, right-angled at R Step 1: Write sine values in each triangle In ΔABC: sin⁡B=ACAB⋯(1)\sin B = \frac{AC}{AB} \quad \cdots (1)   In ΔPQR: sin⁡Q=PRPQ⋯(2)\sin Q = \frac{PR}{PQ} \quad \cdots…

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